Vrijeme: 20:22

Imam 99 problema, no koliko rješenja? | I got 99 problems, but what about solutions? #3

Neka za n > 1, n \in \mathbb{N}, f(n) predstavlja broj realnih rješenja jednadžbe \sin x = \sin (nx) na intervalu [0, \pi].

Odredi zbroj \sum_{n=2}^{2022} f(n).

Let for all n > 1, n \in \mathbb{N}, f(n) be the number of real solutions to the equation \sin x = \sin (nx) on interval [0, \pi]. Determine \sum_{n=2}^{2022} f(n).