Vrijeme: 02:12

Namješten 37 | Overfitting 37 #3

NEMAŠ POJMA - nasmijala se grohotom.

Zatim je otkrila da je f(5)=5.

Ako Matej pretpostavi da je Patricijina funkcija oblika f(x) = ax^3 + bx^2 + cx + d za neke realne brojeve a, b, c i d, koliko bi tada iznosio f(37)?

YOU HAVE NO IDEA - she roared with laughter.

Then she revealed that f(5)=5.

If Matej assumes that Patricija's function is of the form f(x) = ax^3 + bx^2 + cx + d for some real numbers a, b, c and d, what would be the value of f(37)?