Vrijeme: 02:04

Dali smo mu ime! | We gave it a name! #1

Neka je ABC trokut u kome je AB=20, AC=22. Njemu upisana kružnica dodiruje BC,CA,AB u X,Y,Z redom. Neka je D nožište visine iz X na YZ. Ako je \angle BDC=90^{\circ} nađi BC. Rješenje zaokruži na 3 decimale.
Let ABC be a triangle in which AB=20, AC=22. The circle inscribed to it touches BC,CA,AB in X,Y,Z respectively. Let D be the base of the height from X to YZ. If \angle BDC=90^{\circ} find BC. Round the solution to 3 decimal places.