Vrijeme: 02:06

Veoma nasumičan geometrijski lanac | Pretty random geometry chain #1

U četverokutu ABCD vrijedi \angle DAB=\angle ABC=110^{\circ}, \angle BCD=35^{\circ}, \angle CDA=105^{\circ}. Poznato je da AC raspolavlja \angle DAB. Nađi \angle ABD. Rješenje zaokruži na dvije decimale.
In the quadrilateral ABCD, \angle DAB=\angle ABC=110^{\circ}, \angle BCD=35^{\circ}, \angle CDA=105^{\circ} are valid. It is known that AC bisects \angle DAB. Find \angle ABD. Round the solution to two decimal places.