Ponovno je dana kružnica
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radijusa
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sa središtem u
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i točka
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na kružnici. Sada definirajmo
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gdje su
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i
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definirane kao u prvom zadatku ovog lanca. Na sličan način, definirajmo
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gdje su
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i
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definirane kao u drugom zadatku ovog lanca. Sada se vratimo na našu kružnicu
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u ovom zadatku, i neka je
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na
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takva da je
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i da je
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tup. Nadalje, neka je
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na
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takva da je
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i takva da su
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i
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s iste strane pravca
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Naposlijetku, neka je
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na
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takva da je
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Odredi kut
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Odgovor treba napisati u stupnjevima, i treba napisati samo broj (dakle ako je odgovor
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treba upisati samo 123).
Again, consider a circle
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with a radius of
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centered at
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and a point
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on the circle. Now, define
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, where
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and
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are defined as in the first problem of this chain. Similarly, define
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, where
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and
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are defined as in the second problem of this chain. Now, return to our circle
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in this problem, and let
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be a point on
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such that
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and
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is obtuse. Furthermore, let
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be a point on
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such that
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and that
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and
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are on the same side of the line
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. Finally, let
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be a point on
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such that
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. Determine the angle
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. The answer should be written in degrees, and only the number should be provided (so if the answer is
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, you should just write 123).
[lang=hr]
Ponovno je dana kružnica $\sigma$ radijusa $1$ sa središtem u $O$ i točka $P$ na kružnici. Sada definirajmo $a=|XZ|,$ gdje su $X$ i $Z$ definirane kao u prvom zadatku ovog lanca. Na sličan način, definirajmo $b=|HG|,$ gdje su $H$ i $G$ definirane kao u drugom zadatku ovog lanca. Sada se vratimo na našu kružnicu $\sigma$ u ovom zadatku, i neka je $Q$ na $\sigma$ takva da je $|PQ|=a$ i da je $\angle POQ$ tup. Nadalje, neka je $R$ na $\sigma$ takva da je $|PR|=b$ i takva da su $R$ i $Q$ s iste strane pravca $OP.$ Naposlijetku, neka je $S \neq P$ na $\sigma$ takva da je $|RS|=b.$ Odredi kut $\angle QOS.$ Odgovor treba napisati u stupnjevima, i treba napisati samo broj (dakle ako je odgovor $123^\circ,$ treba upisati samo 123).
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[lang=en]
Again, consider a circle $\sigma$ with a radius of $1$ centered at $O$ and a point $P$ on the circle. Now, define $a=|XZ|$, where $X$ and $Z$ are defined as in the first problem of this chain. Similarly, define $b=|HG|$, where $H$ and $G$ are defined as in the second problem of this chain. Now, return to our circle $\sigma$ in this problem, and let $Q$ be a point on $\sigma$ such that $|PQ|=a$ and $\angle POQ$ is obtuse. Furthermore, let $R$ be a point on $\sigma$ such that $|PR|=b$ and that $R$ and $Q$ are on the same side of the line $OP$. Finally, let $S \neq P$ be a point on $\sigma$ such that $|RS|=b$. Determine the angle $\angle QOS$. The answer should be written in degrees, and only the number should be provided (so if the answer is $123^\circ$, you should just write 123).
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