MetaMath '25

U trokutu $ABC$ vrijedi $\left\vert AB \right\vert = \left\vert AC \right\vert$, a simetrala kuta $\angle{ABC}$ siječe stranicu $\overline{AC}$ u točki $D$ tako da je $\left\vert BC \right\vert = \left\vert BD \right\vert + \left\vert AD \right\vert$. Odredi kutove tog trokuta.