Netočno
25. travnja 2023. 09:43 (1 godina, 2 mjeseci)
Let
![A](/media/m/5/a/e/5ae81275ee67d638485e903bdc0e9cde.png)
,
![B](/media/m/c/e/e/ceebc05be717fa6aab8e71b02fe3e4e3.png)
,
![C](/media/m/5/a/b/5ab88f3f735b691e133767fe7ea0483c.png)
,
![D](/media/m/7/0/0/7006c4b57335ab717f8f20960577a9ef.png)
,
![E](/media/m/8/b/0/8b01e755d2253cb9a52f9e451d89ec11.png)
be points such that
![ABCD](/media/m/9/c/e/9ce25711ba18d9663b73c3580de4bf5a.png)
is a cyclic quadrilateral and
![ABDE](/media/m/6/b/2/6b20e9077664c31635bedc510ed8252e.png)
is a parallelogram. The diagonals
![AC](/media/m/6/4/7/647ef3a5d68f07d59d84afe03a9dc655.png)
and
![BD](/media/m/1/1/f/11f65a804e5c922ee28a53b1df04d138.png)
intersect at
![S](/media/m/c/6/3/c63593c3ec0773fa38c2659e08119a75.png)
and the rays
![AB](/media/m/5/2/9/5298bd9e7bc202ac21c423e51da3758e.png)
and
![DC](/media/m/3/4/d/34d909d24fdb3a0dd783c13a369556ce.png)
intersect at
![F](/media/m/3/e/8/3e8bad5df716d332365fca76f53c1743.png)
. Prove that
![\sphericalangle{AFS}=\sphericalangle{ECD}](/media/m/8/5/9/859933cc48906974f479a1122c237f4b.png)
.
%V0
Let $A$, $B$, $C$, $D$, $E$ be points such that $ABCD$ is a cyclic quadrilateral and $ABDE$ is a parallelogram. The diagonals $AC$ and $BD$ intersect at $S$ and the rays $AB$ and $DC$ intersect at $F$. Prove that $\sphericalangle{AFS}=\sphericalangle{ECD}$.
Upozorenje: Ovaj zadatak još niste riješili!
Kliknite ovdje kako biste prikazali rješenje.
Pise se u Latexu
Pise se u Latexu $\int x^2 $