Točno
5. lipnja 2015. 14:44 (9 godine, 1 mjesec)
Upozorenje: Ovaj zadatak još niste riješili!
Kliknite ovdje kako biste prikazali rješenje.
Kliknite ovdje kako biste prikazali rješenje.
![x=a ^2](/media/m/a/0/0/a001ad19734f1fc11324cb3aff55135f.png)
![y=b ^2](/media/m/5/f/7/5f76f6a5ad7194cb529e82860eaf7687.png)
![z=c ^2](/media/m/2/a/1/2a1f8a1bb1fb623d3b5813904cfcfb15.png)
![a \in N](/media/m/7/7/f/77fe1ab99aac016bd39351da8e2a1cbb.png)
![b \in N](/media/m/5/b/e/5bef716283d5a5e60f9f783ff677497e.png)
![c \in N](/media/m/b/1/a/b1a9647cd6658c7e2fdefb44cdfad045.png)
Pa tako vrijede jednadžbe
![a ^2 - b^2 =96](/media/m/6/5/1/651041b3129dcf242ff5d82b1c7b5939.png)
![(a+b)(a-b)=96](/media/m/b/e/6/be696f302850484beb72d5d92343af78.png)
![b ^2 - c^2 =96](/media/m/6/3/1/631503e7dbc0eeb128de70ba2db42779.png)
![(b+c)(b-c)=96](/media/m/6/3/0/630a2fb34fddfd5355e4a0e1dde6f42a.png)
96 je umnožak
![(a+b)(a-b)](/media/m/0/1/d/01d05df3056be32479a73de1967194cd.png)
![(b+c)(b-c)](/media/m/7/b/8/7b81586b45a9d249897f1b31dfee62b5.png)
![a+b](/media/m/5/8/b/58b4b86666ca6eb006117b556ad363e4.png)
![b+c](/media/m/0/3/9/0392b384f589cd2acc0afdf9bd4f8054.png)
![a-b](/media/m/3/0/c/30c4dc4baca89d41475d253434e82468.png)
![b-c](/media/m/9/b/5/9b552033b67e623f64dc9cb1409c7b13.png)
Pa tako jer
![(a+b)+(a-b) \in](/media/m/9/3/9/9391bfe5a14a296950660fc27b9239d4.png)
![2,4,6,8,10,...](/media/m/d/4/8/d484e00d598443d73479ab96c0426859.png)
![(a,b)](/media/m/e/2/6/e263229694cdbeb908488db2d0351f0a.png)
![(b,c)](/media/m/6/f/f/6ff299d48d8dfefdfd958bc63421657a.png)
![(25,23) , (14,10), (11,5), (10,2)](/media/m/f/8/0/f80b086d898cfc0179099cd57b998399.png)
![b](/media/m/e/e/c/eec0d7323095a1f2101fc1a74d069df6.png)
![a=14](/media/m/6/f/9/6f9740c5f9fbb7949299c5271bdc6dd8.png)
![b=10](/media/m/2/6/e/26e3e8d5639e87488070a353f76ce173.png)
![c= 2](/media/m/7/6/7/767d8df7a257280d18093e53d25444ea.png)
pa postoji i samo uređena trojka
![( a ^2 ,b ^2 ,c ^2 )](/media/m/7/1/4/714c552a901a63a5e74509197f3737c3.png)
![(196, 100, 4)](/media/m/a/d/1/ad1c16da7015130902e97ac7f85379e2.png)
![a ^2 - b ^2 =b ^2 -c ^2 =96](/media/m/e/7/a/e7a28ee04e100aa6757b8fce9f1964a6.png)
Ocjene: (1)
Komentari:
ikicic, 7. lipnja 2015. 22:12
PatricijaVelecki, 7. lipnja 2015. 12:06
ikicic, 5. lipnja 2015. 21:34
PatricijaVelecki, 5. lipnja 2015. 21:14
Hvala na ispravku rješenja i upozorenju što bih još trebala dopuniti,ali jednostavno nisam znala kako da drugačije napišem da je to tako jer je
umnožak koji mora biti 96
![(a+b) \times (a-b)](/media/m/4/2/8/4288266ce6c3c61f954d3f6686875184.png)
Cudno malo izgleda formulacija "
mogu biti brojevi (...), jer
mogu biti (...)".
U smislu, zasto
mogu biti tocno ti brojevi?
No, radi se o finesama samo...
![a + b](/media/m/0/8/1/081030fd45eba71e1f6d388b5ee49f43.png)
![a - b](/media/m/5/3/4/53456f7046d9bf4489f94952af3422a4.png)
U smislu, zasto
![a - b](/media/m/5/3/4/53456f7046d9bf4489f94952af3422a4.png)
No, radi se o finesama samo...
Zadnja promjena: PatricijaVelecki, 5. lipnja 2015. 21:14
ikicic, 5. lipnja 2015. 21:04
PatricijaVelecki, 5. lipnja 2015. 19:53
Ja sam mislila da je dovoljno napisati da je 96 djeljiv s
i
i s ovim navedenim brojevima,pa da je odmah slijedilo iz toga da je
>
pa samim time proizlazi i onaj raspored mogućih
i onda na kraju uređeni parovi
![a+b](/media/m/5/8/b/58b4b86666ca6eb006117b556ad363e4.png)
![a-b](/media/m/3/0/c/30c4dc4baca89d41475d253434e82468.png)
![a+b](/media/m/5/8/b/58b4b86666ca6eb006117b556ad363e4.png)
![a-b](/media/m/3/0/c/30c4dc4baca89d41475d253434e82468.png)
![a+b](/media/m/5/8/b/58b4b86666ca6eb006117b556ad363e4.png)
Nedostaju samo malo konkretniji argumenti. Primjerice, dio s mogucim vrijednostima izraza
i
, bilo bi dobro reci otkud takav zakljucak.
Mozes reci recimo da to slijedi iz toga sto je
, pa je
i
.
![a + b](/media/m/0/8/1/081030fd45eba71e1f6d388b5ee49f43.png)
![a - b](/media/m/5/3/4/53456f7046d9bf4489f94952af3422a4.png)
Mozes reci recimo da to slijedi iz toga sto je
![a + b > a - b](/media/m/8/d/5/8d554acebd8b5e1fcbbd9d5340fdd284.png)
![a + b > \sqrt{96}](/media/m/7/5/6/756843187f7a21ff0db95d5f06ce7128.png)
![a - b < \sqrt{96}](/media/m/e/0/b/e0b99ed70585f2819d258e7a0001bb56.png)
ikicic, 5. lipnja 2015. 19:47