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(USS 2) Prove that for a > b^2, the identity \sqrt{a-b\sqrt{a+b\sqrt{a-b\sqrt{a+\cdots}}}}=\sqrt{a-\frac{3}{4}b^2}-\frac{1}{2}b holds.

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Let a, b, c be real numbers such that for every two of the equations x^2+ax+b=0, \quad x^2+bx+c=0, \quad x^2+cx+a=0 there is exactly one real number satisfying both of them. Determine all possible values of a^2+b^2+c^2.
Let n \in \mathbb{Z}^+ and let a, b \in \mathbb{R}. Determine the range of x_0 for which

\sum^n_{i=0} x_i = a \text{ and } \sum^n_{i=0} x^2_i = b,

where x_0, x_1, \ldots , x_n are real variables.
Let P be a polynomial with real coefficients such that P(x) > 0 if x > 0. Prove that there exist polynomials Q and R with nonnegative coefficients such that \displaystyle P(x) = \frac{Q(x)}{R(x)} if x > 0.
Let x, y, z be real numbers each of whose absolute value is different from \displaystyle \frac{1}{\sqrt 3} such that x + y + z = xyz. Prove that
\frac{3x-x^{3}}{1-3x^{2}}+\frac{3y-y^{3}}{1-3y^{2}}+\frac{3z-z^{3}}{1-3z^{2}}=\frac{3x-x^{3}}{1-3x^{2}}\cdot\frac{3y-y^{3}}{1-3y^{2}}\cdot\frac{3z-z^{3}}{1-3z^{2}}
(MON 2) Given reals x_0, x_1, \alpha, \beta, find an expression for the solution of the system x_{n+2} -\alpha x_{n+1} -\beta x_n = 0, \qquad  n= 0, 1, 2, \ldots
(FRA 5) Let \alpha(n) be the number of pairs (x, y) of integers such that x+y = n, 0 \le y \le x, and let \beta(n) be the number of triples (x, y, z) such thatx + y + z = n and 0 \le z \le y \le x. Find a simple relation between \alpha(n) and the integer part of the number \frac{n+2}{2} and the relation among \beta(n), \beta(n -3) and \alpha(n). Then evaluate \beta(n) as a function of the residue of n modulo 6. What can be said about \beta(n) and 1+\frac{n(n+6)}{12}? And what about \frac{(n+3)^2}{6}?
Find the number of triples (x, y, z) with the property x+ y+ z \le n, 0 \le z \le y \le x as a function of the residue of n modulo 6.What can be said about the relation between this number and the number \frac{(n+6)(2n^2+9n+12)}{72}?