Consider a sequence of polynomials
, where
and for every
the following equality holds:
Prove that there exist three real numbers
such that for all
![(x^2 - 4)[P_n^2(x) - 4] = [aP_{n+1}(x) + bP_n(x) + cP_{n-1}(x)]^2.](/media/m/5/9/a/59a55695f2aa8a146a7400a5bdb3a335.png)
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Consider a sequence of polynomials $P_0(x), P_1(x), P_2(x), \ldots, P_n(x), \ldots$, where $P_0(x) = 2, P_1(x) = x$ and for every $n \geq 1$ the following equality holds:
$$P_{n+1}(x) + P_{n-1}(x) = xP_n(x).$$
Prove that there exist three real numbers $a, b, c$ such that for all $n \geq 1,$
$$(x^2 - 4)[P_n^2(x) - 4] = [aP_{n+1}(x) + bP_n(x) + cP_{n-1}(x)]^2.$$
Školjka