Prove that the squares with sides
![\frac{1}{1}, \frac{1}{2}, \frac{1}{3},\ldots](/media/m/8/7/b/87b9793485d7cdd8d75490d40caa774f.png)
may be put into the square with side
![\frac{3}{2}](/media/m/3/c/b/3cbae947c76038acc1305fd3f38b83e7.png)
in such a way that no two of them have any interior point in common.
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Prove that the squares with sides $\frac{1}{1}, \frac{1}{2}, \frac{1}{3},\ldots$ may be put into the square with side $\frac{3}{2}$ in such a way that no two of them have any interior point in common.