The triangle
is inscribed in a circle. The interior bisectors of the angles
and
meet the circle again at
and
respectively. Prove that the area of triangle
is greater than or equal to the area of triangle
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The triangle $ABC$ is inscribed in a circle. The interior bisectors of the angles $A,B$ and $C$ meet the circle again at $A', B'$ and $C'$ respectively. Prove that the area of triangle $A'B'C'$ is greater than or equal to the area of triangle $ABC.$