Given a triangle
, let
and
be points on the side
such that
. If
and
are, respectively, the points of tangency of the incircles of the triangles
and
with the line
, then show that
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Given a triangle $ABC$, let $D$ and $E$ be points on the side $BC$ such that $\angle BAD = \angle CAE$. If $M$ and $N$ are, respectively, the points of tangency of the incircles of the triangles $ABD$ and $ACE$ with the line $BC$, then show that
$$\frac{1}{MB}+\frac{1}{MD}= \frac{1}{NC}+\frac{1}{NE}.$$
Školjka