For three points
in the plane, we define
to be the smallest length of the three heights of the triangle
, where in the case
,
,
are collinear, we set
. Let
,
,
be given points in the plane. Prove that for any point
in the plane,
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For three points $A,B,C$ in the plane, we define $m(ABC)$ to be the smallest length of the three heights of the triangle $ABC$, where in the case $A$, $B$, $C$ are collinear, we set $m(ABC) = 0$. Let $A$, $B$, $C$ be given points in the plane. Prove that for any point $X$ in the plane,
$$m(ABC) \leq m(ABX) + m(AXC) + m(XBC).$$
Školjka