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Let a_{1}, a_{2}...a_{n} be non-negative reals, not all zero. Show that that
(a) The polynomial p(x) = x^{n} - a_{1}x^{n - 1} + ... - a_{n - 1}x - a_{n} has preceisely 1 positive real root R.
(b) let A = \sum_{i = 1}^n a_{i} and B = \sum_{i = 1}^n ia_{i}. Show that A^{A} \leq R^{B}.

Slični zadaci

Show that there exists a bijective function f: \mathbb{N}_{0}\to \mathbb{N}_{0} such that for all m,n\in \mathbb{N}_{0}:
f(3mn + m + n) = 4f(m)f(n) + f(m) + f(n).
Let n be an even positive integer. Prove that there exists a positive integer k such that

k = f(x) \cdot (x+1)^n + g(x) \cdot (x^n + 1)

for some polynomials f(x), g(x) having integer coefficients. If k_0 denotes the least such k, determine k_0 as a function of n, i.e. show that k_0 = 2^q where q is the odd integer determined by n = q \cdot 2^r, r \in \mathbb{N}.

Note: This is variant A6' of the three variants given for this problem.
Let P(x) be the real polynomial function, P(x) = ax^3 + bx^2 + cx + d. Prove that if |P(x)| \leq 1 for all x such that |x| \leq 1, then

|a| + |b| + |c| + |d| \leq 7.
Let a > 2 be given, and starting a_0 = 1, a_1 = a define recursively:

a_{n+1} = \left(\frac{a^2_n}{a^2_{n-1}} - 2 \right) \cdot a_n.

Show that for all integers k > 0, we have: \sum^k_{i = 0} \frac{1}{a_i} < \frac12 \cdot (2 + a - \sqrt{a^2-4}).
Let a_1 \geq a_2 \geq \ldots \geq a_n be real numbers such that for all integers k > 0,

a^k_1 + a^k_2 + \ldots + a^k_n \geq 0.

Let p = max\{|a_1|, \ldots, |a_n|\}. Prove that p = a_1 and that

(x - a_1) \cdot (x - a_2) \cdots (x - a_n) \leq x^n - a^n_1 for all x > a_1.
Suppose that a, b, c > 0 such that abc = 1. Prove that \frac{ab}{ab + a^5 + b^5} + \frac{bc}{bc + b^5 + c^5} + \frac{ca}{ca + c^5 + a^5} \leq 1.