In a contest, there are
![m](/media/m/1/3/6/1361d4850444c055a8a322281f279b39.png)
candidates and
![n](/media/m/a/e/5/ae594d7d1e46f4b979494cf8a815232b.png)
judges, where
![n\geq 3](/media/m/d/f/e/dfe037b8debb8aa67d6ed7ad5e28cc6c.png)
is an odd integer. Each candidate is evaluated by each judge as either pass or fail. Suppose that each pair of judges agrees on at most
![k](/media/m/f/1/3/f135be660b73381aa6bec048f0f79afc.png)
candidates. Prove that
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In a contest, there are $m$ candidates and $n$ judges, where $n\geq 3$ is an odd integer. Each candidate is evaluated by each judge as either pass or fail. Suppose that each pair of judges agrees on at most $k$ candidates. Prove that $${\frac{k}{m}} \geq {\frac{n-1}{2n}}.$$