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Let x_1,x_2,\ldots,x_n be arbitrary real numbers. Prove the inequality

\frac{x_1}{1+x_1^2} + \frac{x_2}{1+x_1^2 + x_2^2} + \cdots + \frac{x_n}{1 + x_1^2 + \cdots + x_n^2} < \sqrt{n}.

Slični zadaci

Let a, b, c be positive real numbers such that \dfrac{1}{a} + \dfrac{1}{b} + \dfrac{1}{c} = a+b+c. Prove that:
\frac{1}{(2a+b+c)^2}+\frac{1}{(a+2b+c)^2}+\frac{1}{(a+b+2c)^2}\leq \frac{3}{16}


Proposed by Juhan Aru, Estonia
Let S\subseteq\mathbb{R} be a set of real numbers. We say that a pair (f, g) of functions from S into S is a Spanish Couple on S, if they satisfy the following conditions:
(i) Both functions are strictly increasing, i.e. f(x) < f(y) and g(x) < g(y) for all x, y\in S with x < y;

(ii) The inequality f\left(g\left(g\left(x\right)\right)\right) < g\left(f\left(x\right)\right) holds for all x\in S.

Decide whether there exists a Spanish Couple on the set S = \mathbb{N} of positive integers; on the set S = \{a - \frac {1}{b}: a, b\in\mathbb{N}\}

Proposed by Hans Zantema, Netherlands
Prove the inequality:

\displaystyle \sum_{i < j}{\frac {a_{i}a_{j}}{a_{i} + a_{j}}}\leq \frac {n}{2(a_{1} + a_{2} + ... + a_{n})}\cdot \sum_{i < j}{a_{i}a_{j}}

for positive reals a_{1}, a_{2}, ..., a_{n}.
The sequence c_{0}, c_{1}, . . . , c_{n}, . . . is defined by c_{0}= 1, c_{1}= 0, and c_{n+2}= c_{n+1}+c_{n} for n \geq 0. Consider the set S of ordered pairs (x, y) for which there is a finite set J of positive integers such that x=\sum_{j \in J}{c_{j}}, y=\sum_{j \in J}{c_{j-1}}. Prove that there exist real numbers \alpha, \beta, and M with the following property: An ordered pair of nonnegative integers (x, y) satisfies the inequality m < \alpha x+\beta y < M if and only if (x, y) \in S.


Remark: A sum over the elements of the empty set is assumed to be 0.
Let a_0, a_1, a_2, \ldots be an arbitrary infinite sequence of positive numbers. Show that the inequality 1 + a_n > a_{n-1} \sqrt[n]{2} holds for infinitely many positive integers n.
Let n be an integer, n \geq 3. Let a_1, a_2, \ldots, a_n be real numbers such that 2 \leq a_i \leq 3 for i = 1, 2, \ldots, n. If s = a_1 + a_2 + \ldots + a_n, prove that \frac{a^{2}_{1}+a^{2}_{2}-a^{2}_{3}}{a_{1}+a_{2}-a_{3}}+\frac{a^{2}_{2}+a^{2}_{3}-a^{2}_{4}}{a_{2}+a_{3}-a_{4}}+\ldots+\frac{a^{2}_{n}+a^{2}_{1}-a^{2}_{2}}{a_{n}+a_{1}-a_{2}}\leq 2s-2n.