Prove: If the sum of all positive divisors of
![n \in \mathbb{Z}^{+}](/media/m/3/6/c/36ca8a826e96085269067410c8c9dc5f.png)
is a power of two, then the number/amount of the divisors is a power of two.
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Prove: If the sum of all positive divisors of $n \in \mathbb{Z}^{+}$ is a power of two, then the number/amount of the divisors is a power of two.