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Given six positive numbers a,b,c,d,e,f such that a < b < c < d < e < f. Let a+c+e=S and b+d+f=T. Prove that
2ST > \sqrt{3(S+T)\left(S(bd + bf + df) + T(ac + ae + ce) \right)}.


Proposed by Sung Yun Kim, South Korea

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