Given a triangle
, with
as its incenter and
as its circumcircle,
intersects
again at
. Let
be a point on the arc
, and
a point on the segment
, such that
. If
is the midpoint of
, prove that the meeting point of the lines
and
lies on
.
Proposed by Tai Wai Ming and Wang Chongli, Hong Kong
%V0
Given a triangle $ABC$, with $I$ as its incenter and $\Gamma$ as its circumcircle, $AI$ intersects $\Gamma$ again at $D$. Let $E$ be a point on the arc $BDC$, and $F$ a point on the segment $BC$, such that $\angle BAF=\angle CAE < \dfrac12\angle BAC$. If $G$ is the midpoint of $IF$, prove that the meeting point of the lines $EI$ and $DG$ lies on $\Gamma$.
Proposed by Tai Wai Ming and Wang Chongli, Hong Kong
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