Školjka

U konveksnom četverokutu $ABCD$ vrijedi $$ \measuredangle BAC = 48^\circ \text{,} \quad\quad \measuredangle CAD = 66^\circ \text{,} \quad\quad \measuredangle CBD = \measuredangle DBA \text{.} $$ Odredi kut $\measuredangle BDC$.