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C is a point on the semicircle diameter AB, between A and B. D is the foot of the perpendicular from C to AB. The circle K_1 is the incircle of ABC, the circle K_2 touches CD,DA and the semicircle, the circle K_3 touches CD,DB and the semicircle. Prove that K_1,K_2 and K_3 have another common tangent apart from AB.

Slični zadaci

Construct a right triangle with given hypotenuse c such that the median drawn to the hypotenuse is the geometric mean of the two legs of the triangle.
An arbitrary point M is selected in the interior of the segment AB. The square AMCD and MBEF are constructed on the same side of AB, with segments AM and MB as their respective bases. The circles circumscribed about these squares, with centers P and Q, intersect at M and also at another point N. Let N' denote the point of intersection of the straight lines AF and BC.

a) Prove that N and N' coincide;

b) Prove that the straight lines MN pass through a fixed point S independent of the choice of M;

c) Find the locus of the midpoints of the segments PQ as M varies between A and B.
Two planes, P and Q, intersect along the line p. The point A is given in the plane P, and the point C in the plane Q; neither of these points lies on the straight line p. Construct an isosceles trapezoid ABCD (with AB \parallel CD) in which a circle can be inscribed, and with vertices B and D lying in planes P and Q respectively.
On the circle K there are given three distinct points A,B,C. Construct (using only a straightedge and a compass) a fourth point D on K such that a circle can be inscribed in the quadrilateral thus obtained.
Let ABCD be a convex quadrilateral with the line CD being tangent to the circle on diameter AB. Prove that the line AB is tangent to the circle on diameter CD if and only if the lines BC and AD are parallel.
It is known that \angle BAC is the smallest angle in the triangle ABC. The points B and C divide the circumcircle of the triangle into two arcs. Let U be an interior point of the arc between B and C which does not contain A. The perpendicular bisectors of AB and AC meet the line AU at V and W, respectively. The lines BV and CW meet at T.

Show that AU = TB + TC.


Alternative formulation:

Four different points A,B,C,D are chosen on a circle \Gamma such that the triangle BCD is not right-angled. Prove that:

(a) The perpendicular bisectors of AB and AC meet the line AD at certain points W and V, respectively, and that the lines CV and BW meet at a certain point T.

(b) The length of one of the line segments AD, BT, and CT is the sum of the lengths of the other two.