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A sequence (u_{n}) is defined by u_{0}=2 \quad u_{1}=\frac{5}{2}, u_{n+1}=u_{n}(u_{n-1}^{2}-2)-u_{1} \quad \textnormal{for  } n=1,\ldots Prove that for any positive integer n we have [u_{n}]=2^{\frac{(2^{n}-(-1)^{n})}{3}}(where {{ Nevaljan tag "x" }} denotes the smallest integer \leq x).

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