Two circles in a plane intersect.

is one of the points of intersection. Starting simultaneously from

two points move with constant speed, each travelling along its own circle in the same sense. The two points return to

simultaneously after one revolution. Prove that there is a fixed point
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in the plane such that the two points are always equidistant from
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Two circles in a plane intersect. $A$ is one of the points of intersection. Starting simultaneously from $A$ two points move with constant speed, each travelling along its own circle in the same sense. The two points return to $A$ simultaneously after one revolution. Prove that there is a fixed point $P$ in the plane such that the two points are always equidistant from $P.$