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In the plane of a triangle ABC, in its exterior, we draw the triangles ABR, BCP, CAQ so that \angle PBC = \angle CAQ = 45\,^{\circ}, \angle BCP = \angle QCA = 30\,^{\circ}, \angle ABR = \angle RAB = 15\,^{\circ}.

Prove that

a.) \angle QRP = 90\,^{\circ}, and

b.) QR = RP.

Slični zadaci

Let a,b,c be real numbers. Consider the quadratic equation in \cos{x} a \cos^2{x}+b \cos{x}+c=0. Using the numbers a,b,c form a quadratic equation in \cos{2x} whose roots are the same as those of the original equation. Compare the equation in \cos{x} and \cos{2x} for a=4, b=2, c=-1.
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Proposed by Germany, DR
In a right-angled triangle ABC let AD be the altitude drawn to the hypotenuse and let the straight line joining the incentres of the triangles ABD, ACD intersect the sides AB, AC at the points K,L respectively. If E and E_1 dnote the areas of triangles ABC and AKL respectively, show that
\frac {E}{E_1} \geq 2.
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