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A circle with center O passes through the vertices A and C of the triangle ABC and intersects the segments AB and BC again at distinct points K and N respectively. Let M be the point of intersection of the circumcircles of triangles ABC and KBN (apart from B). Prove that \angle OMB=90^{\circ}.

Slični zadaci

Construct a right triangle with given hypotenuse c such that the median drawn to the hypotenuse is the geometric mean of the two legs of the triangle.
Three circles of equal radius have a common point O and lie inside a given triangle. Each circle touches a pair of sides of the triangle. Prove that the incenter and the circumcenter of the triangle are collinear with the point O.
A non-isosceles triangle A_{1}A_{2}A_{3} has sides a_{1}, a_{2}, a_{3} with the side a_{i} lying opposite to the vertex A_{i}. Let M_{i} be the midpoint of the side a_{i}, and let T_{i} be the point where the inscribed circle of triangle A_{1}A_{2}A_{3} touches the side a_{i}. Denote by S_{i} the reflection of the point T_{i} in the interior angle bisector of the angle A_{i}. Prove that the lines M_{1}S_{1}, M_{2}S_{2} and M_{3}S_{3} are concurrent.
In an acute-angled triangle ABC the interior bisector of angle A meets BC at L and meets the circumcircle of ABC again at N. From L perpendiculars are drawn to AB and AC, with feet K and M respectively. Prove that the quadrilateral AKNM and the triangle ABC have equal areas.(IMO Problem 2)

Proposed by Soviet Union.
In the plane let \,C\, be a circle, \,L\, a line tangent to the circle \,C,\, and \,M\, a point on \,L. Find the locus of all points \,P\, with the following property: there exists two points \,Q,R\, on \,L\, such that \,M\, is the midpoint of \,QR\, and \,C\, is the inscribed circle of triangle \,PQR.
It is known that \angle BAC is the smallest angle in the triangle ABC. The points B and C divide the circumcircle of the triangle into two arcs. Let U be an interior point of the arc between B and C which does not contain A. The perpendicular bisectors of AB and AC meet the line AU at V and W, respectively. The lines BV and CW meet at T.

Show that AU = TB + TC.


Alternative formulation:

Four different points A,B,C,D are chosen on a circle \Gamma such that the triangle BCD is not right-angled. Prove that:

(a) The perpendicular bisectors of AB and AC meet the line AD at certain points W and V, respectively, and that the lines CV and BW meet at a certain point T.

(b) The length of one of the line segments AD, BT, and CT is the sum of the lengths of the other two.