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Let S_n be the number of sequences (a_1, a_2, \ldots, a_n), where a_i \in \{0,1\}, in which no six consecutive blocks are equal. Prove that S_n \rightarrow \infty when n \rightarrow \infty.

Slični zadaci

A finite number of coins are placed on an infinite row of squares. A sequence of moves is performed as follows: at each stage a square containing more than one coin is chosen. Two coins are taken from this square; one of them is placed on the square immediately to the left while the other is placed on the square immediately to the right of the chosen square. The sequence terminates if at some point there is at most one coin on each square. Given some initial configuration, show that any legal sequence of moves will terminate after the same number of steps and with the same final configuration.
Find all finite sequences (x_0, x_1, \ldots,x_n) such that for every j, 0 \leq j \leq n, x_j equals the number of times j appears in the sequence.
For a positive integer n define a sequence of zeros and ones to be balanced if it contains n zeros and n ones. Two balanced sequences a and b are neighbors if you can move one of the 2n symbols of a to another position to form b. For instance, when n = 4, the balanced sequences 01101001 and 00110101 are neighbors because the third (or fourth) zero in the first sequence can be moved to the first or second position to form the second sequence. Prove that there is a set S of at most \frac{1}{n+1} \binom{2n}{n} balanced sequences such that every balanced sequence is equal to or is a neighbor of at least one sequence in S.
There are n markers, each with one side white and the other side black. In the beginning, these n markers are aligned in a row so that their white sides are all up. In each step, if possible, we choose a marker whose white side is up (but not one of the outermost markers), remove it, and reverse the closest marker to the left of it and also reverse the closest marker to the right of it. Prove that, by a finite sequence of such steps, one can achieve a state with only two markers remaining if and only if n - 1 is not divisible by 3.
For n\ge 2, let S_1, S_2, \ldots, S_{2^n} be 2^n subsets of A = \{1, 2, 3, \ldots, 2^{n + 1}\} that satisfy the following property: There do not exist indices a and b with a < b and elements x, y, z\in A with x < y < z and y, z\in S_a, and x, z\in S_b. Prove that at least one of the sets S_1, S_2, \ldots, S_{2^n} contains no more than 4n elements.

Proposed by Gerhard Woeginger, Netherlands
Five identical empty buckets of 2-liter capacity stand at the vertices of a regular pentagon. Cinderella and her wicked Stepmother go through a sequence of rounds: At the beginning of every round, the Stepmother takes one liter of water from the nearby river and distributes it arbitrarily over the five buckets. Then Cinderella chooses a pair of neighbouring buckets, empties them to the river and puts them back. Then the next round begins. The Stepmother goal's is to make one of these buckets overflow. Cinderella's goal is to prevent this. Can the wicked Stepmother enforce a bucket overflow?

Proposed by Gerhard Woeginger, Netherlands