« Vrati se
Let f(x) = \frac{x^2+1}{2x} for x \neq 0. Define f^{(0)}(x) = x and f^{(n)}(x) = f(f^{(n-1)}(x)) for all positive integers n and x \neq 0. Prove that for all non-negative integers n and x \neq \{-1,0,1\}

\frac{f^{(n)}(x)}{f^{(n+1)}(x)} = 1 + \frac{1}{f \left( \left( \frac{x+1}{x-1} \right)^{2n} \right)}.

Slični zadaci

Let P\!\left(x\right) be a non-constant polynomial with integer coefficients. Prove that there is no function T from the set of integers into the set of integers such that the number of integers x with T^n\!\left(x\right) = x is equal to P\!\left(n\right) for every n \geqslant 1, where T^n denotes the n-fold application of T.

Proposed by Jozsef Pelikan, Hungary
For every n\in\mathbb{N} let d(n) denote the number of (positive) divisors of n. Find all functions f: \mathbb{N}\to\mathbb{N} with the following properties: d\left(f(x)\right) = x for all x\in\mathbb{N}. f(xy) divides (x - 1)y^{xy - 1}f(x) for all x, y\in\mathbb{N}.

Proposed by Bruno Le Floch, France
Find all surjective functions f: \mathbb{N} \mapsto \mathbb{N} such that for every m,n \in \mathbb{N} and every prime p, the number f(m + n) is divisible by p if and only if f(m) + f(n) is divisible by p.

Author: Mohsen Jamaali and Nima Ahmadi Pour Anari, Iran
Let A be a non-empty set of positive integers. Suppose that there are positive integers b_1,\ldots b_n and c_1,\ldots,c_n such that

- for each i the set b_iA+c_i=\left\{b_ia+c_i\colon a\in A\right\} is a subset of A, and

- the sets b_iA+c_i and b_jA+c_j are disjoint whenever i\ne j

Prove that {1\over b_1}+\,\ldots\,+{1\over b_n}\leq1.
Let n be a positive integer that is not a perfect cube. Define real numbers a,b,c by

a=\root3\of n\kern1.5pt,\qquad b={1\over a-[a]}\kern1pt,\qquad c={1\over b-[b]}\kern1.5pt,

where [x] denotes the integer part of x. Prove that there are infinitely many such integers n with the property that there exist integers r,s,t, not all zero, such that ra+sb+tc=0.
a > 0 and b, c are integers such that acb^2 is a square-free positive integer P. For example P could be 3*5, but not 3^2*5. Let f(n) be the number of pairs of integers d, e such that ad^2 + 2bde + ce^2= n. Show thatf(n) is finite and that f(n) = f(P^{k}n) for every positive integer k.

Original Statement:

Let a,b,c be given integers a > 0, ac-b^2 = P = P_1 \cdots P_n where P_1 \cdots P_n are (distinct) prime numbers. Let M(n) denote the number of pairs of integers (x,y) for which ax^2 + 2bxy + cy^2 = n. Prove that M(n) is finite and M(n) = M(P_k \cdot n) for every integer k \geq 0. Note that the "n" in P_N and the "n" in M(n) do not have to be the same.