The lengths of the sides of a convex hexagon
satisfy
,
,
. Prove that:
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The lengths of the sides of a convex hexagon $ABCDEF$ satisfy $AB = BC$, $CD = DE$, $EF = FA$. Prove that:
$$\frac {BC}{BE} + \frac {DE}{DA} + \frac {FA}{FC} \geq \frac {3}{2}.$$
Školjka