Let
be a triangle for which there exists an interior point
such that
. Let the lines
and
meet the sides
and
at
and
respectively. Prove that
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Let $ABC$ be a triangle for which there exists an interior point $F$ such that $\angle AFB=\angle BFC=\angle CFA$. Let the lines $BF$ and $CF$ meet the sides $AC$ and $AB$ at $D$ and $E$ respectively. Prove that
$$AB+AC\geq4DE.$$
Školjka