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Let ABC be a trapezoid with parallel sides AB > CD. Points K and L lie on the line segments AB and CD, respectively, so that \frac {AK}{KB} = \frac {DL}{LC}. Suppose that there are points P and Q on the line segment KL satisfying \angle{APB} = \angle{BCD} and \angle{CQD} = \angle{ABC}. Prove that the points P, Q, B and C are concylic.

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What is the maximal number of regions a circle can be divided in by segments joining n points on the boundary of the circle ?

Posted already on the board I think...
A circle S bisects a circle S' if it cuts S' at opposite ends of a diameter. S_A, S_B,S_C are circles with distinct centers A, B, C (respectively).
Show that A, B, C are collinear iff there is no unique circle S which bisects each of S_A, S_B,S_C . Show that if there is more than one circle S which bisects each of S_A, S_B,S_C , then all such circles pass through two fixed points. Find these points.

Original Statement:

A circle S is said to cut a circle \Sigma diametrically if and only if their common chord is a diameter of \Sigma.
Let S_A, S_B, S_C be three circles with distinct centres A,B,C respectively. Prove that A,B,C are collinear if and only if there is no unique circle S which cuts each of S_A, S_B, S_C diametrically. Prove further that if there exists more than one circle S which cuts each S_A, S_B, S_C diametrically, then all such circles S pass through two fixed points. Locate these points in relation to the circles S_A, S_B, S_C.
Let S be a finite set of points in the plane such that no three of them are on a line. For each convex polygon P whose vertices are in S, let a(P) be the number of vertices of P, and let b(P) be the number of points of S which are outside P. A line segment, a point, and the empty set are considered as convex polygons of 2, 1, and 0 vertices respectively. Prove that for every real number x:

\sum_{P}{x^{a(P)}(1 - x)^{b(P)}} = 1, where the sum is taken over all convex polygons with vertices in S.

Alternative formulation:

Let M be a finite point set in the plane and no three points are collinear. A subset A of M will be called round if its elements is the set of vertices of a convex A -gon V(A). For each round subset let r(A) be the number of points from M which are exterior from the convex A -gon V(A). Subsets with 0,1 and 2 elements are always round, its corresponding polygons are the empty set, a point or a segment, respectively (for which all other points that are not vertices of the polygon are exterior). For each round subset A of M construct the polynomial
P_A(x) = x^{|A|}(1 - x)^{r(A)}.
Show that the sum of polynomials for all round subsets is exactly the polynomial P(x) = 1.
A cake has the form of an n x n square composed of n^{2} unit squares. Strawberries lie on some of the unit squares so that each row or column contains exactly one strawberry; call this arrangement A. Let B be another such arrangement. Suppose that every grid rectangle with one vertex at the top left corner of the cake contains no fewer strawberries of arrangement B than of arrangement A.

Prove that arrangement B can be obtained from A by performing a number of switches, defined as follows: A switch consists in selecting a grid rectangle with only two strawberries, situated at its top right corner and bottom left corner, and moving these two strawberries to the other two corners of that rectangle.
Consider a convex pentagon ABCDE such that
\angle BAC = \angle CAD = \angle DAE\ \ \ ,\ \ \ \angle ABC = \angle ACD = \angle ADE
Let P be the point of intersection of the lines BD and CE. Prove that the line AP passes through the midpoint of the side CD.
Given trapezoid ABCD with parallel sides AB and CD, assume that there exist points E on line BC outside segment BC, and F inside segment AD such that \angle DAE = \angle CBF. Denote by I the point of intersection of CD and EF, and by J the point of intersection of AB and EF. Let K be the midpoint of segment EF, assume it does not lie on line AB. Prove that I belongs to the circumcircle of ABK if and only if K belongs to the circumcircle of CDJ.

Proposed by Charles Leytem, Luxembourg