Denote by
![M](/media/m/f/7/f/f7f312cf6ba459a332de8db3b8f906c4.png)
midpoint of side
![BC](/media/m/5/0/0/5005d4d5eac1b420fbabb76c83fc63ad.png)
in an isosceles triangle
![\triangle ABC](/media/m/1/f/3/1f3c3c0f3e134a169655f9511ba6ea82.png)
with
![AC = AB](/media/m/c/c/8/cc8f47a064ff2150f74b4bed99422b11.png)
. Take a point
![X](/media/m/9/2/8/92802f174fc4967315c2d8002c426164.png)
on a smaller arc
![\widehat{MA}](/media/m/7/c/1/7c15ea5f8c3f059fbc3545c7cce79d3a.png)
of circumcircle of triangle
![\triangle ABM](/media/m/a/4/6/a46087d896fc7ad5906475cab3c43ada.png)
. Denote by
![T](/media/m/0/1/6/016d42c58f7f5f06bdf8af6b85141914.png)
point inside of angle
![BMA](/media/m/e/8/c/e8cc040db9289843077820838aa263f3.png)
such that
![\angle TMX = 90](/media/m/8/1/0/810f9168ecd103aa3df759342b992564.png)
and
![TX = BX](/media/m/e/c/f/ecf6a6b96373d7484c4d9ae84e33aae4.png)
.
Prove that
![\angle MTB - \angle CTM](/media/m/5/b/6/5b63b4660d88c05725b884bfdc97dd63.png)
does not depend on choice of
![X](/media/m/9/2/8/92802f174fc4967315c2d8002c426164.png)
.
Author: unknown author, Canada
%V0
Denote by $M$ midpoint of side $BC$ in an isosceles triangle $\triangle ABC$ with $AC = AB$. Take a point $X$ on a smaller arc $\widehat{MA}$ of circumcircle of triangle $\triangle ABM$. Denote by $T$ point inside of angle $BMA$ such that $\angle TMX = 90$ and $TX = BX$.
Prove that $\angle MTB - \angle CTM$ does not depend on choice of $X$.
Author: unknown author, Canada