Državno natjecanje 2011 SŠ2 4
Dodao/la:
arhiva1. travnja 2012. U trokutu

vrijedi

, a simetrala kuta

siječe stranicu

u točki

tako da je
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. Odredi kutove tog trokuta.
%V0
U trokutu $ABC$ vrijedi $\left\vert AB \right\vert = \left\vert AC \right\vert$, a simetrala kuta $\angle{ABC}$ siječe stranicu $\overline{AC}$ u točki $D$ tako da je $\left\vert BC \right\vert = \left\vert BD \right\vert + \left\vert AD \right\vert$. Odredi kutove tog trokuta.
Izvor: Državno natjecanje iz matematike 2011