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The function F is defined on the set of nonnegative integers and takes nonnegative integer values satisfying the following conditions: for every n \geq 0,

(i) F(4n) = F(2n) + F(n),
(ii) F(4n + 2) = F(4n) + 1,
(iii) F(2n + 1) = F(2n) + 1.

Prove that for each positive integer m, the number of integers n with 0 \leq n < 2^m and F(4n) = F(3n) is F(2^{m + 1}).

Slični zadaci

Let S be the set of all pairs (m,n) of relatively prime positive integers m,n with n even and m < n. For s = (m,n) \in S write n = 2^k \cdot n_o where k, n_0 are positive integers with n_0 odd and define f(s) = (n_0, m + n - n_0). Prove that f is a function from S to S and that for each s = (m,n) \in S, there exists a positive integer t \leq \frac{m+n+1}{4} such that f^t(s) = s, where f^t(s) = \underbrace{ (f \circ f \circ \cdots \circ f) }_{t \text{ times}}(s).

If m+n is a prime number which does not divide 2^k - 1 for k = 1,2, \ldots, m+n-2, prove that the smallest value t which satisfies the above conditions is \left [\frac{m+n+1}{4} \right ] where \left[ x \right] denotes the greatest integer \leq x.
Let a, b, c be positive integers satisfying the conditions b > 2a and c > 2b. Show that there exists a real number \lambda with the property that all the three numbers \lambda a, \lambda b, \lambda c have their fractional parts lying in the interval \left(\frac {1}{3}, \frac {2}{3} \right].
Let P be a cubic polynomial given by P(x)=ax^3+bx^2+cx+d, where a,b,c,d are integers and a\ne0. Suppose that xP(x)=yP(y) for infinitely many pairs x,y of integers with x\ne y. Prove that the equation P(x)=0 has an integer root.
Find all functions f: \mathbb{N^{*}}\to \mathbb{N^{*}} satisfying
\left(f^{2}\left(m\right)+f\left(n\right)\right) \mid \left(m^{2}+n\right)^{2}
for any two positive integers m and n.

Remark. The abbreviation \mathbb{N^{*}} stands for the set of all positive integers:
\mathbb{N^{*}}=\left\{1,2,3,...\right\}.
By f^{2}\left(m\right), we mean \left(f\left(m\right)\right)^{2} (and not f\left(f\left(m\right)\right)).
For an integer m, denote by t(m) the unique number in \{1, 2, 3\} such that m + t(m) is a multiple of 3. A function f: \mathbb{Z}\to\mathbb{Z} satisfies f( - 1) = 0, f(0) = 1, f(1) = - 1 and f\left(2^{n} + m\right) = f\left(2^n - t(m)\right) - f(m) for all integers m, n\ge 0 with 2^n > m. Prove that f(3p)\ge 0 holds for all integers p\ge 0.

Proposed by Gerhard Woeginger, Austria
Let f be a non-constant function from the set of positive integers into the set of positive integer, such that a-b divides f\!\left(a\right)-f\!\left(b\right) for all distinct positive integers a, b. Prove that there exist infinitely many primes p such that p divides f\!\left(c\right) for some positive integer c.

Proposed by Juhan Aru, Estonia