Županijsko natjecanje iz matematike 2015, SŠ3 A 4
Dodao/la:
arhiva22. ožujka 2015. U konveksnom četverokutu

vrijedi

,

i

. Ako je

, izračunaj

.
%V0
U konveksnom četverokutu $ABCD$ vrijedi $\sphericalangle BAD = 50^\circ$, $\sphericalangle ADB = 80^\circ$ i $\sphericalangle ACB = 40^\circ$. Ako je $\sphericalangle DBC = 30^\circ + \sphericalangle BDC$, izračunaj $\sphericalangle BDC$.
Izvor: Županijsko natjecanje iz matematike 2015