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Given four distinct parallel planes, prove that there exists a regular tetrahedron with a vertex on each plane.

Slični zadaci

An isosceles trapezoid with bases a and c and altitude h is given.

a) On the axis of symmetry of this trapezoid, find all points P such that both legs of the trapezoid subtend right angles at P;

b) Calculate the distance of p from either base;

c) Determine under what conditions such points P actually exist. Discuss various cases that might arise.
Given the tetrahedron ABCD whose edges AB and CD have lengths a and b respectively. The distance between the skew lines AB and CD is d, and the angle between them is \omega. Tetrahedron ABCD is divided into two solids by plane \epsilon, parallel to lines AB and CD. The ratio of the distances of \epsilon from AB and CD is equal to k. Compute the ratio of the volumes of the two solids obtained.
Prove that every tetrahedron has a vertex whose three edges have the right lengths to form a triangle.
In the tetrahedron ABCD,\angle BDC=90^o and the foot of the perpendicular from D to ABC is the intersection of the altitudes of ABC. Prove that: (AB+BC+CA)^2\le6(AD^2+BD^2+CD^2). When do we have equality?
All faces of the tetrahedron ABCD are acute-angled. Take a point X in the interior of the segment AB, and similarly Y in BC, Z in CD and T in AD.

a.) If \angle DAB+\angle BCD\ne\angle CDA+\angle ABC, then prove none of the closed paths XYZTX has minimal length;

b.) If \angle DAB+\angle BCD=\angle CDA+\angle ABC, then there are infinitely many shortest paths XYZTX, each with length 2AC\sin k, where 2k=\angle BAC+\angle CAD+\angle DAB.
Prove the following assertion: The four altitudes of a tetrahedron ABCD intersect in a point if and only if
AB^2 + CD^2 = BC^2 + AD^2 = CA^2 + BD^2.