Državno natjecanje 2010 SŠ1 4
Dodao/la:
arhiva1. travnja 2012. U trokutu
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vrijedi
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, a
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je polovište dužine

. Kružnica sa središtem u točki
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siječe pravac
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u točkama
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i
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.
Dokaži da je

.
%V0
U trokutu $ABC$ vrijedi $\angle{ACB} = 90^{\circ} + \frac{1}{2} \angle{CBA}$, a $M$ je polovište dužine $\overline{BC}$. Kružnica sa središtem u točki $A$ siječe pravac $BC$ u točkama $M$ i $D$.
Dokaži da je $\left\vert MD \right\vert = \left\vert AB \right\vert$.
Izvor: Državno natjecanje iz matematike 2010