Let be a prime odd number. Is it possible to find natural numbers such that the sum of the squares of these numbers is divisible by the sum of these numbers?
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$(CZS 2)$ Let $p$ be a prime odd number. Is it possible to find $p-1$ natural numbers $n + 1, n + 2, . . . , n + p -1$ such that the sum of the squares of these numbers is divisible by the sum of these numbers?
Izvor: Međunarodna matematička olimpijada, shortlist 1969
Školjka 
Let 
be a prime odd number. Is it possible to find 
natural numbers 
such that the sum of the squares of these numbers is divisible by the sum of these numbers?