IMO Shortlist 1969 problem 50
Dodao/la:
arhiva2. travnja 2012. ![(NET 5)](/media/m/4/4/6/4468076d1d83db6faa54a7bb71041195.png)
The bisectors of the exterior angles of a pentagon
![B_1B_2B_3B_4B_5](/media/m/1/d/3/1d35656d31b675f5996edbe4cb3e9469.png)
form another pentagon
![A_1A_2A_3A_4A_5.](/media/m/c/b/5/cb544f57c553789988197a40e0a50006.png)
Construct
![B_1B_2B_3B_4B_5](/media/m/1/d/3/1d35656d31b675f5996edbe4cb3e9469.png)
from the given pentagon
%V0
$(NET 5)$ The bisectors of the exterior angles of a pentagon $B_1B_2B_3B_4B_5$ form another pentagon $A_1A_2A_3A_4A_5.$ Construct $B_1B_2B_3B_4B_5$ from the given pentagon $A_1A_2A_3A_4A_5.$
Izvor: Međunarodna matematička olimpijada, shortlist 1969