IMO Shortlist 1977 problem 12
Dodao/la:
arhiva2. travnja 2012. In the interior of a square

we construct the equilateral triangles

Prove that the midpoints of the four segments

and the midpoints of the eight segments

are the 12 vertices of a regular dodecagon.
%V0
In the interior of a square $ABCD$ we construct the equilateral triangles $ABK, BCL, CDM, DAN.$ Prove that the midpoints of the four segments $KL, LM, MN, NK$ and the midpoints of the eight segments $AK, BK, BL, CL, CM, DM, DN, AN$ are the 12 vertices of a regular dodecagon.
Izvor: Međunarodna matematička olimpijada, shortlist 1977