IMO Shortlist 2004 problem G4


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2. travnja 2012.
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In a convex quadrilateral ABCD, the diagonal BD bisects neither the angle ABC nor the angle CDA. The point P lies inside ABCD and satisfies \angle PBC=\angle DBA \quad \text{and} \quad \angle PDC = \angle BDA.
Prove that ABCD is a cyclic quadrilateral if and only if AP=CP.
Izvor: Međunarodna matematička olimpijada, shortlist 2004